In a series LCR circuit, the voltage drop across the resistance is 8 V , across the inductor is 6 V and across the capacitor is 12 V . Then,

Question

In a series LCR circuit, the voltage drop across the resistance is 8 V , across the inductor is 6 V and across the capacitor is 12 V . Then,, the voltage of the source will be leading the current in the circuit, the voltage drop across each element will be less than the applied voltage, the power factor of the circuit will be 4 3, none of these

MARKS App · Accepted Answer

Since, cos ⁡ ϕ = R Z = I R I Z = 8 10 = 4 5 (Also cos ⁡ ϕ can never be greater than 1 ) Hence, (c) is wrong Also I X C > I X L ⇒ X C > X L ∴ Current will be leading. In an LCR circuit, V = V L - V C 2 + V R 2 = 6 - 12 2 + 8 2 V = 10 V , which is less than the voltage drop across the capacitor.

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