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Question: Answered & Verified by Expert
In a series resonant LCR circuit, the voltage across $R$ is 100 volts and $R=1 \mathrm{k} \Omega$ with $C=2 \mu \mathrm{F}$. The resonant frequency $\omega$ is $200 \mathrm{rad} / \mathrm{s}$. At resonance the voltage across $L$ is
PhysicsAlternating CurrentJEE MainJEE Main 2006
Options:
  • A
    $4 \times 10^{-3} \mathrm{~V}$
  • B
    $2.5 \times 10^{-2} \mathrm{~V}$
  • C
    $40 \mathrm{~V}$
  • D
    $250 \mathrm{~V}$
Solution:
2848 Upvotes Verified Answer
The correct answer is:
$250 \mathrm{~V}$
$\mathrm{i}=\frac{100}{1000}=0.1 \mathrm{~A}$
$V_L=V_C=\frac{0.1}{200 \times 2 \times 10^{-6}}=250 \mathrm{~V}$

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