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In a set of reactions propionic acid yielded a compound 'd'.
\(\mathrm{CH}_2 \mathrm{CH}_2 \mathrm{COOH}\xrightarrow{\mathrm{SOCl}_2}{ }^{\prime} b^{\prime} \xrightarrow{\mathrm{NH}_3}{ }^{\prime} c^{\prime} \xrightarrow[\mathrm{Br}_2]{\mathrm{KOH}}{ }^{\prime} \mathrm{d}^{\prime}\)
The structure of 'd' would be:
Options:
\(\mathrm{CH}_2 \mathrm{CH}_2 \mathrm{COOH}\xrightarrow{\mathrm{SOCl}_2}{ }^{\prime} b^{\prime} \xrightarrow{\mathrm{NH}_3}{ }^{\prime} c^{\prime} \xrightarrow[\mathrm{Br}_2]{\mathrm{KOH}}{ }^{\prime} \mathrm{d}^{\prime}\)
The structure of 'd' would be:
Solution:
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Verified Answer
The correct answer is:
$\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{NH}_2$
Related Theory
When an amide is treated with bromine in an aqueous or ethanolic solution of sodium hydroxide, degradation of amide takes place leading to the formation of primary amine. This reaction is known as Hoffmann bromamide degradation reaction.
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