In a simple harmonic motion, let $\mathrm{f}$ be the acceleration and $\mathrm{T}$ be the time period. If $x$ denotes the displacement, then |fT| vs. X graph will look like,

Question

In a simple harmonic motion, let $\mathrm{f}$ be the acceleration and $\mathrm{T}$ be the time period. If $x$ denotes the displacement, then |fT| vs. X graph will look like,, , , ,

MARKS App · Accepted Answer

$\begin{gathered}\text {Hint: } F \cdot T=\omega^2 x \cdot \frac{2 \pi}{\omega}=2 \pi \omega x \ \because \text { F.T }=2 \pi \omega x\end{gathered}$

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