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In a simultaneous throw of a pair of dice, the probability of getting a total more than \( 7 \) is
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The correct answer is:
\( \frac{5}{12} \)
Total number of outcomes of getting sum more than \( 7 \), that is, \( \{8,9,10,11,12\} \) is \( 15 \)
Total number of outcomes is \( 36 \).
So, required probability is given by \( \frac{15}{36}=\frac{5}{12} \)
Total number of outcomes is \( 36 \).
So, required probability is given by \( \frac{15}{36}=\frac{5}{12} \)
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