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In a single slit experiment, a parallel beam of green light of wavelength $550 \mathrm{~nm}$ passes through a slit of width $0.20 \mathrm{~mm}$. The transmitted light is collected on a screen $100 \mathrm{~cm}$ away. The distance of first order minima from the central maximum will be $x \times 10^{-5} \mathrm{~m}$. The value of $x$ is :
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The correct answer is:
275
$\mathrm{y}=\frac{\lambda \mathrm{D}}{\mathrm{d}}=\frac{550 \times 10^{-9} \times 100 \times 10^{-2}}{0.2 \times 10^{-3}}=275$
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