In a single-slit diffraction pattern, the position of first secondary maximum is at 3 0 ∘ , then what will be the angular position of second minima?

Question

In a single-slit diffraction pattern, the position of first secondary maximum is at 3 0 ∘ , then what will be the angular position of second minima?, sin - 1 2 / 3, sin - 1 ⁡ ( 1 ), sin - 1 ⁡ 1 / 2, None

MARKS App · Accepted Answer

For first secondary maxima, sin θ 1 = 1 + 1 2 λ a = 3 λ 2 a ⇒ sin 3 0 o = 3 λ 2 a ⇒ λ a = 1 3 For second minima, sin ⁡ θ = 2 λ a = 2 3 or θ = sin - 1 2 / 3

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