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In a solid, atom $M$ occupies ccp lattice and $1 / 3^{\text {rd }}$ of tetrahedral voids are occupied by atom $N$. Find the formula of solid formed by $M$ and $N$.
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$M_3 N_2$
Suppose number of $M$ atoms $=n$ Then number of tetrahedral sites $=2 n$ Number of $N$ atoms $=\frac{1}{3}(2 n)$ Ratio $M: N=n: \frac{2}{3} n=3: 2$, i.e., formula is $M_3 N_2$
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