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Question: Answered & Verified by Expert
In a sports competition, a javelin in thrown at an angle $45^{\circ}$, which recorded a range of $90 \mathrm{~m}$. The maximum height reached by the javelin is
(Neglect air resistance and acceleration due to gravity $=10 \mathrm{~ms}^{-2}$ )
PhysicsMotion In Two DimensionsAP EAMCETAP EAMCET 2022 (06 Jul Shift 1)
Options:
  • A $45 \mathrm{~m}$
  • B $30 \mathrm{~m}$
  • C $22.5 \mathrm{~m}$
  • D $30 \sqrt{2} \mathrm{~m}$
Solution:
1266 Upvotes Verified Answer
The correct answer is: $22.5 \mathrm{~m}$
$\mathrm{R}=\frac{\mathrm{H}}{4} \tan \theta=\frac{90}{4} \tan 45^{\circ}=22.5 \mathrm{~m}$

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