Search any question & find its solution
Question:
Answered & Verified by Expert
In a transformer number of turns in primary circuit is 500 and in secondary circuit number of turns is 10 . The load resistance is $10 \Omega$ and voltage of secondary coil is $50 \mathrm{~V}$. Then find the current in primary circuit.
Options:
Solution:
1137 Upvotes
Verified Answer
The correct answer is:
$0.1 \mathrm{~A}$
Given, $N_1=500, N_2=10, R_L=10 \Omega$
$V_2=50 \mathrm{~V}$
Current in the secondary circuit is
$\begin{aligned} & i_2=\frac{V_2}{R_L}=\frac{50}{10}=5 \mathrm{~A} \\ & \frac{i_1}{i_2}=\frac{N_2}{N_1} \Rightarrow \frac{i_1}{5}=\frac{10}{500} \Rightarrow i_1=0.1 \mathrm{~A}\end{aligned}$
$V_2=50 \mathrm{~V}$
Current in the secondary circuit is
$\begin{aligned} & i_2=\frac{V_2}{R_L}=\frac{50}{10}=5 \mathrm{~A} \\ & \frac{i_1}{i_2}=\frac{N_2}{N_1} \Rightarrow \frac{i_1}{5}=\frac{10}{500} \Rightarrow i_1=0.1 \mathrm{~A}\end{aligned}$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.