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In a transformer, number of turns in the primary coil are 140 and that in the secondary coil are 280. If current in primary coil is $4 \mathrm{~A}$, then that in the secondary coil is
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2 A
2 A
$I_1 N_1=I_2 N_2 \Rightarrow I_2=\frac{4 \times 140}{280}=2 \mathrm{~A}$
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