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In a triangle $\mathrm{ABC}$, if $\frac{r}{r_1}=\frac{1}{2}$, then 4
$$
\tan \frac{\mathrm{A}}{2}\left(\tan \frac{\mathrm{B}}{2}+\tan \frac{\mathrm{C}}{2}\right)=
$$
Options:
$$
\tan \frac{\mathrm{A}}{2}\left(\tan \frac{\mathrm{B}}{2}+\tan \frac{\mathrm{C}}{2}\right)=
$$
Solution:
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Verified Answer
The correct answer is:
2
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