In a triangle ABC , if tan ( 2 A − B ) = 3 1 tan ( 2 A + B ) then a : b =, 2 : 1, 3 : 1, 4 : 1, 1 : 3

In a triangle ABC , if tan ( 2 A − B ) = 3 1 tan ( 2 A + B ) then a : b =

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In a triangle $\mathrm{ABC}$, if $\tan \left(\frac{A-B}{2}\right)=\frac{1}{3} \tan \left(\frac{A+B}{2}\right)$ then $a: b=$

MathematicsProperties of TrianglesAP EAMCETAP EAMCET 2017 (26 Apr Shift 2)

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Solution:

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The correct answer is: $2: 1$

No solution. Refer to answer key.

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