In a triangle P Q R , the co-ordinates of the points P and Q are - 2 , 4 and 4 , - 2 respectively. If the equation of the perpendicular bisector of P R is 2 x - y + 2 = 0 , then the centre of the circumcircle of the Δ P Q R is:

Question

In a triangle P Q R , the co-ordinates of the points P and Q are - 2 , 4 and 4 , - 2 respectively. If the equation of the perpendicular bisector of P R is 2 x - y + 2 = 0 , then the centre of the circumcircle of the Δ P Q R is:, – 1 , 0, – 2 , – 2, 0 , 2, 1 , 4

MARKS App · Accepted Answer

Perpendicular bisector of P R is 2 x - y + 2 = 0 Midpoint of P Q is M 1 , 1 Equation of perpendicular bisector of P Q is y = x . Point of intersection of equations P R and P Q is circumcentre. So, circumcentre is - 2 , - 2

Search any question & find its solution

Looking for more such questions to practice?