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In a uniformly charged sphere of total charge $Q$ and radius $R$, the electric field $E$ is plotted as a function of distance from the centre. The graph which would correspond to the above will be
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Verified Answer
The correct answer is:
$\overrightarrow{\mathrm{E}}_{\text {inside }}=\left(\frac{1}{4 \pi \varepsilon_0} \frac{\mathrm{Q}}{\mathrm{R}^3}\right) \overrightarrow{\mathrm{r}}$
$\overrightarrow{\mathrm{E}}_{\text {outside }}\left(\frac{1}{4 \pi \varepsilon_0} \frac{\mathrm{Q}}{\mathrm{r}^3}\right) \overrightarrow{\mathrm{r}}$
$\therefore$
$\overrightarrow{\mathrm{E}}_{\text {outside }}\left(\frac{1}{4 \pi \varepsilon_0} \frac{\mathrm{Q}}{\mathrm{r}^3}\right) \overrightarrow{\mathrm{r}}$
$\therefore$
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