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In a vessel containing $\mathrm{SO}_3, \mathrm{SO}_2$ and $\mathrm{O}_2$ at equilibrium, some helium gas is introduced so that the total pressure increases while temperature and volume remain constant. According to Le-Chatelier.principle the dissociation of $\mathrm{SO}_3$
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The volume is kept constant. Hence, the concentration of the gases does not change. The partial pressure of the gases in the reaction does not change, even though we have increased the total pressure by adding helium. Therefore, there is no change in equilibrium.
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