In a Young's double slit experiment, the fringe width is $ \beta $. If the entire arrangement is now placed inside a liquid of refractive index $ \mu $, the fringe width will become,

Question

In a Young's double slit experiment, the fringe width is $ \beta $. If the entire arrangement is now placed inside a liquid of refractive index $ \mu $, the fringe width will become,, $ \mu \beta $, $ \frac{\beta}{\mu} $, $ \frac{\beta}{\mu+1} $, $ \frac{\beta}{\mu-1} $

MARKS App · Accepted Answer

The fringe width, β = λ D d ⇒ β ∝ λ . When the entire arrangement is placed inside a liquid, the wavelength of light changes. The new wavelength becomes, λ ' = λ μ β β ' = λ λ ' ⇒ β β ' = λ λ μ β ' = β μ .

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