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In a Young's double slit experiment the intensity of light at each slit is $\mathrm{I}_{0}$. Interference pattern in observed along a direction parallel to the line $\mathrm{S}_{1} \mathrm{~S}_{2}$, on screen S.-
The minimum, maximum, and the intensity averaged over the entire screen are respectively
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The minimum, maximum, and the intensity averaged over the entire screen are respectively
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Verified Answer
The correct answer is:
$0,4 \mathrm{I}_{0}, 2 \mathrm{I}_{0}$
$\begin{array}{l}
\mathrm{I}_{\min }=0 \\
\mathrm{I}_{\mathrm{max}}=4 \mathrm{I}_{0} \\
\mathrm{I}_{\mathrm{av}}=2 \mathrm{I}_{0}
\end{array}$
\mathrm{I}_{\min }=0 \\
\mathrm{I}_{\mathrm{max}}=4 \mathrm{I}_{0} \\
\mathrm{I}_{\mathrm{av}}=2 \mathrm{I}_{0}
\end{array}$
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