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In a Young's double slit experiment, the separation between the two slits is $d$ and the wavelength of the light is $\lambda$. The intensity of light falling on slit 1 is four times the intensity of light falling on slit 2 . Choose the correct choice(s),
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The correct answers are:
If $d=\lambda$, the screen will contain only one maximum
,
If $\lambda < d < 2 \lambda$, at least one more maximum (besides the central maximum) will be observed on the screen
If $d=\lambda$, the screen will contain only one maximum
,
If $\lambda < d < 2 \lambda$, at least one more maximum (besides the central maximum) will be observed on the screen
For $d=\lambda$, there will be only one, acentral maxima.
For $\lambda < d < 2 \lambda$, there will be three maximas on the screen corresponding to path difference, $\Delta x=0$ and $\Delta x=\pm \lambda$ correct options are (a) and (b).
For $\lambda < d < 2 \lambda$, there will be three maximas on the screen corresponding to path difference, $\Delta x=0$ and $\Delta x=\pm \lambda$ correct options are (a) and (b).
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