In △ ABC , if a = 2 ( 3 + 1 ) , B = 4 5 ∘ and C = 6 0 ∘ , then the area (in sq.units) of that triangle is

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In $\triangle \mathrm{ABC}$, if $a=2(\sqrt{3}+1), B=45^{\circ}$ and $C=60^{\circ}$, then the area (in sq.units) of that triangle is

MathematicsProperties of TrianglesAP EAMCETAP EAMCET 2017 (24 Apr Shift 2)

Options:

A $2 \sqrt{3}$
B $6$
C $6+2 \sqrt{3}$
D $6-2 \sqrt{3}$

Solution:

2208 Upvotes Verified Answer

The correct answer is: $6+2 \sqrt{3}$

No solution. Refer to answer key.

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