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In $\triangle \mathrm{ABC}$, if $\left|\begin{array}{lll}a & b & c \\ b & c & a \\ c & a & b\end{array}\right|=0$, then $\cos \mathrm{A} \cos \mathrm{B}+\cos \mathrm{B} \cos \mathrm{C}+\cos \mathrm{C} \cos \mathrm{A}=$
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The correct answer is:
$\frac{3}{4}$
No solution. Refer to answer key.
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