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In $\triangle \mathrm{ABC}$, if ' $\mathrm{S}$ ' is the circumcentre and ' $\mathrm{O}$ ' is the orthocentre then $\overline{O A}+\overline{O B}+\overline{O C}=$
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The correct answer is:
$2(\overline{A S}+\overline{B S}+\overline{C S})$
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