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In an \(A C\) circuit the potential differences across an inductance and resistance joined in series are respectively \(16 \mathrm{~V}\) and \(20 \mathrm{~V}\). The total potential difference of the source is
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The correct answer is:
\(25.6 \mathrm{~V}\)
\(V_L=16 \mathrm{~V}, V_R=20 \mathrm{~V}\).
In the inductor the current lags by \(\frac{\pi}{2}\).
\(\begin{array}{ll}
\therefore \quad V=\sqrt{V_L^2+V_R^2}=\sqrt{256+400} \\
\therefore \quad V_{\text {total }}=25.6 \mathrm{~V} .
\end{array}\)
In the inductor the current lags by \(\frac{\pi}{2}\).
\(\begin{array}{ll}
\therefore \quad V=\sqrt{V_L^2+V_R^2}=\sqrt{256+400} \\
\therefore \quad V_{\text {total }}=25.6 \mathrm{~V} .
\end{array}\)
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