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In an ac circuit $I=100 \sin 200 \pi t$. The time required for the current to achieve its peak value will be
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The correct answer is:
$\frac{1}{400} \mathrm{sec}$
The current takes $\frac{T}{4} \sec$ to reach the peak value.
In the given question $\frac{2 \pi}{T}=200 \pi \Rightarrow T=\frac{1}{100} \mathrm{sec}$
$\therefore$ Time to reach the peak value $=\frac{1}{400} \mathrm{sec}$
In the given question $\frac{2 \pi}{T}=200 \pi \Rightarrow T=\frac{1}{100} \mathrm{sec}$
$\therefore$ Time to reach the peak value $=\frac{1}{400} \mathrm{sec}$
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