In an A.C. circuit resistance $R$, inductance $L$ and capacitance $C$ are in parallel. The value of $R$ is $50 \Omega$, inductive reactance $\mathrm{X}_{\mathrm{L}}=40 \Omega$ and capacitive reactance $\mathrm{X}_{\mathrm{C}}=25 \Omega$. Then the reading of ammeter will be:

Question

In an A.C. circuit resistance $R$, inductance $L$ and capacitance $C$ are in parallel. The value of $R$ is $50 \Omega$, inductive reactance $\mathrm{X}_{\mathrm{L}}=40 \Omega$ and capacitive reactance $\mathrm{X}_{\mathrm{C}}=25 \Omega$. Then the reading of ammeter will be:, $10.2 \mathrm{~A}$, $5 \mathrm{~A}$, $17 \mathrm{~A}$, $7 \mathrm{~A}$

MARKS App · Accepted Answer

$\begin{aligned} & \mathrm{I}=\sqrt{\mathrm{I}^2{ }_{\mathrm{R}}+\left(\mathrm{I}_{\mathrm{C}}-\mathrm{I}_{\mathrm{L}}\right)^2} \ & \mathrm{I}_{\mathrm{R}}=\frac{\mathrm{E}}{\mathrm{R}}=\frac{200}{50}=4 \mathrm{~A} \ & \mathrm{I}_{\mathrm{C}}=\frac{\mathrm{E}}{\mathrm{X}_{\mathrm{C}}}=\frac{200}{25}=8 \mathrm{~A} \ & \mathrm{I}_{\mathrm{L}}=\frac{\mathrm{E}}{\mathrm{X}_{\mathrm{L}}}=\frac{200}{40}=5 \mathrm{~A} \ & \mathrm{I}=\sqrt{(4)^2+(8-5)^2} \ & \mathrm{I}=\sqrt{16+9}=\sqrt{25} \ & \mathrm{I}=5 \mathrm{~A} \end{aligned}$

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