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In an $\mathrm{AC}$ circuit, the current is $i=5 \sin \left(100 t-\frac{\pi}{2}\right) \mathrm{A}$ and voltage is $e=200 \sin (100 t)$ volt. Power consumption in the circuit is $\left(\cos 90^{\circ}=0\right)$
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$\begin{aligned} \mathrm{P} & =\mathrm{I}_{\mathrm{rms}} \mathrm{V}_{\mathrm{rms}} \cos \phi \\ \phi & =90^{\circ} \\ \therefore \quad \mathrm{P} & =0 \quad\left(\because \cos 90^{\circ}=0\right)\end{aligned}$
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