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In an AC circuit, the instantaneous values of emf and current are $e=200 \sin 314 t$ volt and $I=\sin \left(314 t+\frac{\pi}{3}\right)$ amp. The average power
consumed in watt is
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consumed in watt is
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Verified Answer
The correct answer is:
50
$V_{\mathrm{rms}}=\frac{200}{\sqrt{2}}, I_{\mathrm{rms}}=\frac{1}{\sqrt{2}}$
$\therefore \quad P=V_{\mathrm{rms}} I_{\mathrm{rms}} \cos \phi$
$$
=\frac{200}{\sqrt{2}} \frac{1}{\sqrt{2}} \cos \frac{\pi}{3}=50 \mathrm{~W}
$$
$\therefore \quad P=V_{\mathrm{rms}} I_{\mathrm{rms}} \cos \phi$
$$
=\frac{200}{\sqrt{2}} \frac{1}{\sqrt{2}} \cos \frac{\pi}{3}=50 \mathrm{~W}
$$
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