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In an a.c. circuit the voltage applied is $\mathrm{E}=\mathrm{E}_0 \sin \omega \mathrm{t}$. The resulting current in the circuit is $\mathrm{I}=\mathrm{I}_0 \sin \left(\omega \mathrm{t}-\frac{\pi}{2}\right)$. The power consumption in the circuit is given by

PhysicsAlternating CurrentJEE MainJEE Main 2007

Options:

A
$\mathrm{P}=\frac{\mathrm{E}_0 \mathrm{I}_0}{\sqrt{2}}$
B
$\mathrm{P}=$ zero
C
$\mathrm{P}=\frac{\mathrm{E}_0 \mathrm{I}_0}{2}$
D
$\mathrm{P} \sqrt{2} \mathrm{E}_0 \mathrm{I}_0$

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