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Question: Answered & Verified by Expert
In an adiabatic expansion of a gas initial and final temperatures are $T_1$ and $T_2$ respectively then the change in internal energy of the gas is
$$
\text { [R = gas constant, } \mathrm{Y}=\text { adiabatic ratio }]
$$
PhysicsThermodynamicsMHT CETMHT CET 2022 (05 Aug Shift 1)
Options:
  • A zero
  • B $\frac{n R}{\gamma-1}\left(T_1-T_2\right)$
  • C $\frac{\mathrm{nR}}{\mathrm{Y}-1}\left(\mathrm{~T}_2-\mathrm{T}_1\right)$
  • D $\mathrm{nR}\left(\mathrm{T}_1-\mathrm{T}_2\right)$
Solution:
2881 Upvotes Verified Answer
The correct answer is: $\frac{\mathrm{nR}}{\mathrm{Y}-1}\left(\mathrm{~T}_2-\mathrm{T}_1\right)$
The correct option is (C).
Concept: In adiabatic process work done is equal to change in internal energy as there is not enough time for heat transfer.
$\Delta \mathrm{W}=\Delta \mathrm{U}$
Work done can be calculated by relation: $\Delta \mathrm{W}=\int \mathrm{p} \mathrm{dV}$.

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