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In an atom, total number of electrons having quantum numbers \(\mathrm{n}=4,\left|\mathrm{~m}_l\right|=1\) and \(\mathrm{m}_{\mathrm{s}}=-\frac{1}{2}\) is
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Verified Answer
The correct answer is:
6
$\mathrm{n}=4$
$\ell \quad \mathrm{m}_{\ell}$
$\begin{array}{ll}
0 & 0 \\
1 & -1,0,+1 \\
2 & -2,-1,0,+1,+2,+3
\end{array}$
So number of orbital associated with
$\mathrm{n}=4,\left|\mathrm{~m}_{\ell}\right|=1 \text { are } 6$
Now each orbital contain one $e^{-}$with $m_s=-\frac{1}{2}$
$\ell \quad \mathrm{m}_{\ell}$
$\begin{array}{ll}
0 & 0 \\
1 & -1,0,+1 \\
2 & -2,-1,0,+1,+2,+3
\end{array}$
So number of orbital associated with
$\mathrm{n}=4,\left|\mathrm{~m}_{\ell}\right|=1 \text { are } 6$
Now each orbital contain one $e^{-}$with $m_s=-\frac{1}{2}$
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