In an E. coli strain, i gene gets mutated, and its product cannot bind the inducer molecule. If the growth medium is provided with lactose, what will be the outcome?

Question

In an E. coli strain, i gene gets mutated, and its product cannot bind the inducer molecule. If the growth medium is provided with lactose, what will be the outcome?, z , y , a genes will be transcribed, z , y , a genes will not be translated, RNA polymerase will bind the promoter region, Only z gene will get transcribed

MARKS App · Accepted Answer

Given above is the functioning of the normal lac operon in E. coli . The question says that due to mutation, the product of i gene which is the repressor, cannot bind to the inducer molecule which is lactose. The repressor gene binds to the operator region and does not allow the binding of RNA polymerase to the promoter region in the mRNA molecule. If the repressor is absent, then it will not bind to the operator, the binding of RNA polymerase to the promoter region will be open always and there will be the transcription of lac z, y, and a genes.

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