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Question: Answered & Verified by Expert
In an electrical circuit, the voltage is measured as $V=(200 \pm 4)$ volt and the current is measured as $I=(20 \pm 0.2) \mathrm{A}$. The value of the resistance is:
PhysicsCurrent ElectricityNEETNEET 2024 (Re-NEET)
Options:
  • A $(10 \pm 4.2) \Omega$
  • B $(10 \pm 0.3) \Omega$
  • C $(10 \pm 0.1) \Omega$
  • D $(10 \pm 0.8) \Omega$
Solution:
2431 Upvotes Verified Answer
The correct answer is: $(10 \pm 0.3) \Omega$
$R=\frac{V}{l}=\frac{200}{20}=10 \Omega$
$\frac{\Delta R}{R}=\frac{\Delta V}{V}+\frac{\Delta l}{l}=\frac{4}{200}+\frac{0.2}{20}=\frac{4+2}{200}=\frac{6}{200}$
$\Rightarrow \Delta R=\frac{6}{200} \times R=\frac{6}{20}=\frac{3}{10}=0.3 \Omega$
$\therefore$ Resistance $=R \pm \Delta R=(10 \pm 0.3) \Omega$

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