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In an ellipse, the distance between its foci is 6 and minor axis is 8. Then its eccentricity is
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Verified Answer
The correct answer is:
$\frac{3}{5}$
$\frac{3}{5}$
$2 a e=6 \Rightarrow a e=3$
$2 b=8 \Rightarrow b=4$
$b^2=a^2\left(1-e^2\right)$
$16=a^2-a^2 e^2$
$a^2=16+9=25$
$a=5$
$\therefore e=\frac{3}{a}=\frac{3}{5}$
$2 b=8 \Rightarrow b=4$
$b^2=a^2\left(1-e^2\right)$
$16=a^2-a^2 e^2$
$a^2=16+9=25$
$a=5$
$\therefore e=\frac{3}{a}=\frac{3}{5}$
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