In an energy recycling process, $ x \mathrm{~g} $ of steam at $ 100^{\circ} \mathrm{C} $ becomes water at $ 100^{\circ} \mathrm{C} $ which converts $ y \mathrm{~g} $ of ice at $ 0^{\circ} \mathrm{C} $ into water at $ 100^{\circ} \mathrm{C} $. The ratio of $ \frac{x}{y} $ will be

Question

In an energy recycling process, $ x \mathrm{~g} $ of steam at $ 100^{\circ} \mathrm{C} $ becomes water at $ 100^{\circ} \mathrm{C} $ which converts $ y \mathrm{~g} $ of ice at $ 0^{\circ} \mathrm{C} $ into water at $ 100^{\circ} \mathrm{C} $. The ratio of $ \frac{x}{y} $ will be, $ \frac{1}{3} $, $ \frac{2}{3} $, $ 3 . $, $ 2 $.

MARKS App · Accepted Answer

Specific heat of water = 4200 J kg - 1 K - 1 Specific latent heat of fusion = 3.36 × 10 5 J kg Specific latent heat of vaporization = 22.68 × 10 5 J kg - 1 = x × 10 - 3 × 22.68 × 10 5 = y × 10 - 3 × 3.36 × 10 5 + y × 10 - 3 × 4200 × 100 ∴ x y = 7.56 22.68 = 1 3

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