In an experiment according to set up, when E 1 = 12 V and internal resistance zero, e = 2 V . The galvanometer reads zero, then X would be-

Question

In an experiment according to set up, when E 1 = 12 V and internal resistance zero, e = 2 V . The galvanometer reads zero, then X would be-, 200, 500, 100, 10

MARKS App · Accepted Answer

Voltage across X is 2 v So E 1 500 + X X = 2 ⇒ 12 500 + X X = 2 ⇒ 12 X = 1000 + 2 X ⇒ 10 X = 1000 X = 100 Ω

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