In an experiment, DNA is treated with the compound which tends to place itself amongst the stacks of nitrogenous base pairs. As a result of this, the distance between two consecutive base increases. From $0.34-0.44 \mathrm{~nm}$ calculate the length of DNA double helix (which has $2 \times 10^9 \mathrm{bp}$ ) in the presence of saturation of this compound.