In an experiment for determination of refractive index of glass of a prism by i v/s δ plot, it was found that a ray incident at angle 35 o , suffers a deviation of 40 o and that it emerges at angle 79 o . In that case which of the following is closest to the maximum possible value of the refractive index?

Question

In an experiment for determination of refractive index of glass of a prism by i v/s δ plot, it was found that a ray incident at angle 35 o , suffers a deviation of 40 o and that it emerges at angle 79 o . In that case which of the following is closest to the maximum possible value of the refractive index?, 1.7, 1.8, 1.5, 1.6

MARKS App · Accepted Answer

i = 35 o , δ = 40 o , e = 79 o δ = i + e - A 40 o = 35 o + 79 o - A A = 74 o And r 1 + r 2 = A = 74 o Since δ m i n 40 o μ sin ⁡ 74 + 40 2 sin ⁡ 37 μ m a x = 1.44

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