In an experiment to determine the gravitational acceleration g of a place with the help of a simple pendulum, the measured time period squared is plotted against the string length of the pendulum in the figure. What is the value of g at the place?

Question

In an experiment to determine the gravitational acceleration g of a place with the help of a simple pendulum, the measured time period squared is plotted against the string length of the pendulum in the figure. What is the value of g at the place?, 10 . 0 m s - 2, 9 . 87 m s - 2, 9 . 91 m s - 2, 9 . 81 m s - 2

MARKS App · Accepted Answer

T = 2 π L g ⇒ g = 4 π 2 L T 2 T 2 L = 4 π 2 g = tanθ = slope of graph ⇒ g = 4 π 2 tanθ ∵ tanθ = 8 − 2 2 − 0.5 = 6 1.5 = 4 ⇒ g = 4 π 2 4 = ( 3.14 ) 2 = π 2 = 3 . 1 4 2 = 9 . 8 7 m s - 2

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