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Question: Answered & Verified by Expert
In an experiment to estimate the size of a molecule of oleic acid. $1 \mathrm{~mL}$ of oleic acid is dissolved in $19 \mathrm{~mL}$ of alcohol. Then $1 \mathrm{~mL}$ of this solution is diluted to $20 \mathrm{~mL}$ by adding alcohol. Now, 1 drop of this diluted solution is placed on water in a shallow trough. The solution spreads over the surface of water forming one molecule thick layer. Now, lycopodium powder is sprinkled evenly over the film and its diameter is measured. Knowing the volume of the drop and area of the film we can calculate the thickness of the film which will give us the size of oleic acid molecule. Read the passage carefullyand answer the following questions
(a) Why do we dissolve oleic acid in alcohol?
(b) What is the role of lycopodium powder?
(c) What would be the volume of oleic acid in each $\mathrm{mL}$ of solution prepared?
(d) How will you calculate the volume of $n$ drops of this solution of oleic acid?
(e) What will be the volume of oleic acid in one drop of this solution?
PhysicsUnits and Dimensions
Solution:
1327 Upvotes Verified Answer
(a) To get a molecular level we have to reduce the concentration of oleic acid by dissolving it in a proper solvent.
Oleic acid does not dissolve in ionic solvent water hence, it is dissolved in organic solvent alcohol.
(b) Lycopodium powder spreads over the entire water surface when it is sprinkled evenly. When a drop of prepared solution is dropped on water, oleic acid does not dissolve in water. Instead it spreads on the water surface pushing the lycopodium powder away to clear a circular area where the drop falls. So, we can measure the area over which oleic acid spreads.
(c) The concentration of oleic acid in each $\mathrm{mL}$ of solution prepared volume of oleic acid
$$
=\frac{1}{20} \mathrm{~mL} \times \frac{1}{20}=\frac{1}{400} \mathrm{~mL}
$$
(d) Volume of $n$ drops of solution of oleic acid can be calculated by means of a burette and measuring cylinder and measuring the number of drops if $n$ drops are in $1 \mathrm{~mL}$, then volume of $1 \mathrm{drop}=\frac{1}{n} \mathrm{ml}$.
(e) The volume of 1 drop of solution in $\left(\frac{1}{n}\right) \mathrm{ml}$. If $n$ drops of the solution make $1 \mathrm{~mL}$, the volume of oleic acid in one drop will be $\frac{1}{(400) n} \mathrm{~mL}$.

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