Search any question & find its solution
Question:
Answered & Verified by Expert
In an experiment to study photoelectric effect the observed variation of stopping potential with frequency of incident radiation is as shown in the figure. The slope and $y$-intercept are respectively
Options:
Solution:
1738 Upvotes
Verified Answer
The correct answer is:
$\frac{h}{e},-\frac{h v_0}{e}$
The maximum kinetic energy of emitted
photoelectrons is given as
$\begin{array}{ll}\Rightarrow & e V_0=h v-\phi_0 \\ \Rightarrow & V_0=\left(\frac{h}{e}\right) v-\frac{\phi_0}{e}\end{array}$
Comparing with $y=m x+c$, we get
$\begin{aligned} \quad m & =\frac{h}{e} \text { and } c=-\frac{\phi_0}{e}=-\frac{h v_0}{e} \\ \therefore \text { Slope } & =m=\frac{h}{e}\end{aligned}$
photoelectrons is given as
$\begin{array}{ll}\Rightarrow & e V_0=h v-\phi_0 \\ \Rightarrow & V_0=\left(\frac{h}{e}\right) v-\frac{\phi_0}{e}\end{array}$
Comparing with $y=m x+c$, we get
$\begin{aligned} \quad m & =\frac{h}{e} \text { and } c=-\frac{\phi_0}{e}=-\frac{h v_0}{e} \\ \therefore \text { Slope } & =m=\frac{h}{e}\end{aligned}$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.