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In an ideal gas equation which is constant?
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Verified Answer
The correct answer is:
Universal gas constant
According to ideal gas equation, $\mathrm{pV}=\mathrm{nRT}$
where, $\mathrm{p}=$ pressure, $\mathrm{V}=$ volume
$\mathrm{n}=$ no. of mole, $\mathrm{T}=$ temperature
$\mathrm{R}=$ universal gas constant
$\mathrm{R}=8.314 \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}$
$=0.08205 \mathrm{~L} \mathrm{~atm} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}=1.99 \mathrm{cal} \mathrm{mol}^{-1} \mathrm{~K}^{-1}$
$=5.189 \times 10^{19} \mathrm{eV} \mathrm{mol}^{-1} \mathrm{~K}^{-1}$
where, $\mathrm{p}=$ pressure, $\mathrm{V}=$ volume
$\mathrm{n}=$ no. of mole, $\mathrm{T}=$ temperature
$\mathrm{R}=$ universal gas constant
$\mathrm{R}=8.314 \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}$
$=0.08205 \mathrm{~L} \mathrm{~atm} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}=1.99 \mathrm{cal} \mathrm{mol}^{-1} \mathrm{~K}^{-1}$
$=5.189 \times 10^{19} \mathrm{eV} \mathrm{mol}^{-1} \mathrm{~K}^{-1}$
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