Search any question & find its solution
Question:
Answered & Verified by Expert
In an ideal parallel $L C$ circuit, the capacitor is charged by connecting it to a d.c. source which is then disconnected. The current in the circuit
Options:
Solution:
2103 Upvotes
Verified Answer
The correct answer is:
oscillates instantaneously.
When the capacitor is connected to a d.c. source and then disconnected, it gets charged and then it starts discharging through the inductor. An induced emf is produced in the circuit which opposes the growth of current in $L$. When the capacitor is fully discharged, the electric energy stored in the capacitor (i.e. $1 / 2 q^{2 / C}$ ) gets converted fully into magnetic field energy $\left(1 / 2 L I^2\right)$. As soon as the discharge of the capacitor is complete, current stops and the magnetic flux linked with $L$ starts collapsing. Therefore, an induced emf is again developed which starts recharging the capacitor in the opposite direction. When the recharging is completed, all magnetic energy stored in $L$ appears as the electric energy between the plates of the capacitor. The entire process keeps on repeating and the energy taken from the cell keeps on oscillating between $C$ and $L$. Hence the current in the circuit starts oscillating as soon as the d.c. source charging the capacitor is disconnected.


Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.