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In an inelastic collision an electron excites as hydrogen atom from its ground state to a M-shell state. A second electron collides instantaneously with the excited hydrogen atom in the M-State and ionizes it. At least how much energy the second electron transfers to the atom in the M-state?
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The correct answer is:
\(+1.51 \mathrm{eV}\)
Hints: \(E_m=-\frac{13.6}{(3)^2}=-1.51\)
Minimum energy required by electron should be \(+1.51 \mathrm{eV}\)
Minimum energy required by electron should be \(+1.51 \mathrm{eV}\)
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