Search any question & find its solution
Question:
Answered & Verified by Expert
In an isochoric process if $t_1=27^{\circ} \mathrm{C}$ and, $t_2=127^{\circ} \mathrm{C}$ then $\frac{P_1}{P_2}$ will be equal to $\left[P_1\right.$ and $P_2$ are the pressures at $t_1{ }^{\circ} \mathrm{C}$ and $t_2^{\circ} \mathrm{C}$ respectively]
Options:
Solution:
2535 Upvotes
Verified Answer
The correct answer is:
$\frac{3}{4}$
At constant volume $P \propto T \therefore \frac{P_1}{P_2}=\frac{T_1}{T_2}=\frac{300}{400}=\frac{3}{4}$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.