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In an isosceles $\triangle A B C$, the coordinates of vertices $B$ and $C$ of the base $B C$ are $(3,2)$ and $(2,3)$ respectively. If the equation of the line $A B$ is $3 y=2 x$, then the equation of the line $A C$ is
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$2 y=3 x$
$\triangle A B C$ is an isosceles triangle $B \equiv(3,2)$ and $C \equiv(2,3)$
$B$ and $C$ are symmetric about the line $y=x$
Equation of $A B=3 y=2 x$
Equation of $A C$ is symmetric about $y=x$
$\therefore$ Equation of $A C=2 y=3 x$
$B$ and $C$ are symmetric about the line $y=x$
Equation of $A B=3 y=2 x$
Equation of $A C$ is symmetric about $y=x$
$\therefore$ Equation of $A C=2 y=3 x$
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