In an NPN transistor circuit, the collector current is 10 mA . If 90% of the electrons emitted reach the collector, the emitter current (i,) and base current (iB) are given by

Question

In an NPN transistor circuit, the collector current is 10 mA . If 90% of the electrons emitted reach the collector, the emitter current (i,) and base current (iB) are given by, i F ​ = − 1 m A , i B ​ = 9 m A, i B = 9 m A , i B = − 1 m A, i B ​ = 1 m A , i B ​ = 11 mA, i E ​ = 11 mA , i B ​ = 1 mA

MARKS App · Accepted Answer

i C ​ = 100 90 ​ × i E ​ ⇒ 10 = 0.9 × i E ​ = 1.1 mA Also i E ​ = i B ​ + i C ​ ⇒ i B ​ = 11 − 10 = 1 mA .

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