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Question: Answered & Verified by Expert
In any triangle $\mathrm{ABC}, \mathrm{a}=18, \mathrm{~b}=24$ and $\mathrm{c}=30$. Then what is $\begin{array}{ll}\text { sin C equal to : } & {}\end{array}$
MathematicsProperties of TrianglesNDANDA 2013 (Phase 1)
Options:
  • A $\frac{1}{4}$
  • B $\frac{1}{3}$
  • C $\frac{1}{2}$
  • D 1
Solution:
2145 Upvotes Verified Answer
The correct answer is: 1
$\cos C=\frac{a^{2}+b^{2}-c^{2}}{2 a b}$
$\Rightarrow \cos C=\frac{(18)^{2}+(24)^{2}-(30)^{2}}{2 \times 18 \times 24}=\frac{9+16-5^{2}}{2 \times 3 \times 4}=0$
Now, $\sin C=\sqrt{1-\cos ^{2} C}=\sqrt{1-0}=1$
Hence $\sin C=1$

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