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In astronomical observations, signals observed from the distant stars are generally weak. If the photon detector receives a total of \(3.15 \times 10^{-18} \mathrm{~J}\) from the radiations of \(600 \mathrm{~nm}\), calculate the number of photons received by the detector.
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Energy of one photon \(=h v=h \frac{\mathrm{c}}{\lambda}\)
\(=\frac{\left(6.626 \times 10^{-34} \mathrm{Js}\right)\left(3 \times 10^8 \mathrm{~ms}^{-1}\right)}{\left(600 \times 10^{-9} \mathrm{~m}\right)}=3.313 \times 10^{-19} \mathrm{~J}\)
Total energy received \(=3.15 \times 10^{-18} \mathrm{~J}\)
\(\therefore\) No. of photons received \(=\frac{3.15 \times 10^{-18}}{3.313 \times 10^{-19}}=9.51=10\)
\(=\frac{\left(6.626 \times 10^{-34} \mathrm{Js}\right)\left(3 \times 10^8 \mathrm{~ms}^{-1}\right)}{\left(600 \times 10^{-9} \mathrm{~m}\right)}=3.313 \times 10^{-19} \mathrm{~J}\)
Total energy received \(=3.15 \times 10^{-18} \mathrm{~J}\)
\(\therefore\) No. of photons received \(=\frac{3.15 \times 10^{-18}}{3.313 \times 10^{-19}}=9.51=10\)
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