Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
In baptism experiment, the distance between source and eyepiece is 1.2m, the distance between two virtual sources is 0.84mm. Then, the wavelength of light used if eyepiece is to be moved transverselythrough a distance of 2.799cm to shift 30 fringes is
PhysicsWave OpticsMHT CETMHT CET 2019 (02 May Shift 1)
Options:
  • A 6533
  • B 6537
  • C 6535
  • D 6351
Solution:
1045 Upvotes Verified Answer
The correct answer is: 6351
y=n.λDd
2.799×10-2=30λ1.20.84×10-3
λ=6351

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.