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In Bohr model of atom, radius of hydrogen atom in ground state is $\mathrm{r}_1$ and radius of $\mathrm{He}^{+}$ion in ground state is $\mathrm{r}_2$. Which of the following is correct?
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Verified Answer
The correct answer is:
$\frac{r_2}{r_1}=\frac{1}{2}$
$r_n=a_0 \times \frac{n^2}{z}$
$\underline{\text {For H-atom}}$
$r_1=a_0$
$\underline{\text {Also, For}}$ $\underline {\mathrm{He}^{+}}$ - $\underline{\text { ion }}$
$r_2=a_0 \times \frac{1^2}{2}=\frac{r_1}{2}$
$\therefore \frac{r_2}{r_1}=\frac{1}{2}$
$\underline{\text {For H-atom}}$
$r_1=a_0$
$\underline{\text {Also, For}}$ $\underline {\mathrm{He}^{+}}$ - $\underline{\text { ion }}$
$r_2=a_0 \times \frac{1^2}{2}=\frac{r_1}{2}$
$\therefore \frac{r_2}{r_1}=\frac{1}{2}$
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